Why Synthetic Aperture (Radar or Sonar)?

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ApertureLab · Why Synthetic Aperture?

Step 1 of 7

Start with one element.

An element is a single transducer: the smallest piece of<br>a sonar that turns an electrical signal into sound, and turns a returning<br>echo back into a voltage. A microphone and a loudspeaker in one part, tuned<br>to a narrow band and coupled to water instead of air.

It has a physical size. The element used throughout this page is 33 mm<br>long. The sonar drives it at 300 kHz, and sound travels at roughly 1500 m/s<br>in seawater, so one wavelength is 5 mm.

Those two lengths, the size of the element and the wavelength, decide<br>almost everything that follows. Every array on this page, real or synthetic,<br>is built out of elements like this one.

33 mm

electrical drive

one element<br>acoustic wave, λ = 5 mm<br>300 kHz in seawater

One transducer element. Its length D and the acoustic<br>wavelength λ are the only two numbers the rest of this page needs.

Step 2 of 7

One element cannot tell two things apart.

Sound leaving an element does not travel as a pencil. It spreads into a<br>cone, and the angular width of that cone is set by the ratio of wavelength<br>to element size:

θ ≈ λ / D = 5 mm / 33 mm = 0.15 rad = 8.6°

Now put a target in the water. The echo comes back at a time that pins<br>down its range precisely, and a wideband pulse separates two<br>objects a few centimeters apart in range no matter how far away they are.<br>Range resolution does not degrade with distance.

Direction is another matter. All the echo tells you is that something is<br>somewhere inside the cone. Two objects at the same range, anywhere across<br>that cone, send back echoes that arrive at the same instant and add<br>together. They are one measurement, not two.

And the cone widens with distance, so the ambiguity grows in proportion<br>to range:

0.30 m<br>across the beam at 2 m

3.8 m<br>at 25 m

7.5 m<br>at 50 m

15 m<br>at 100 m

θ ≈ λ/D = 8.6°

3.8 m<br>7.5 m<br>15 m

25 m<br>50 m<br>100 m

two targets, same range, both inside the beam;<br>the echoes arrive together and add

along-track

range

Drawn to scale in both axes: the wedge really is 8.6 degrees<br>wide, and the footprint really does reach 15 m across at 100 m. Range<br>resolution stays fixed while along-track resolution degrades linearly with<br>distance.

So the picture a single element produces is sharp in one direction and<br>smeared in the other, and the smearing gets worse the further out you look.<br>That asymmetry is the entire reason synthetic aperture exists.

A note on conventions

Beamwidth can be quoted as the half-power width, the first-null width,<br>or the nominal λ/D. They differ by factors near one. This page uses<br>λ/D throughout so the numbers stay comparable from step to step.

Step 3 of 7

Directionality is not a property of a transducer.

Take a second element and place it a distance d from the first, then add<br>the two received signals together.

For a wave arriving straight ahead , the crests reach both<br>elements at the same moment. The two voltages are in step, and the sum is<br>twice either one.

For a wave arriving off to the side , one element is<br>further along the incoming wavefront than the other. The extra distance the<br>wave has to cover is d sin θ. When that extra distance is<br>half a wavelength, the two voltages are exactly opposite and the sum is<br>zero. The pair is blind in that direction.

Sweep the angle below and watch it happen.

Arrival angle of the incoming wave

0° straight ahead<br>30° first null<br>90° endfire

geometry

broadside

d = λ<br>amber: the extra distance<br>the far element has to cover

what each element receives

A + B<br>time →

amplitude of the sum, against arrival angle

2×<br>sum

-90°<br>-60°<br>-30°<br>0°<br>30°<br>60°<br>90°

24°<br>arrival angle

0.41 λ<br>extra path d sin θ

146°<br>phase difference

0.59 ×<br>sum, vs. one element

Drag the angle and watch B slide against A. Where the<br>extra path reaches half a wavelength the two are opposite and the sum<br>collapses to nothing; the curve underneath is that cancellation plotted<br>across every angle, which is the beam pattern of a pair of elements.<br>Spacing here is one wavelength, which puts the first null at a visible<br>30 degrees. The second peak at 90 degrees is a real ambiguity, and<br>suppressing it is one of the jobs the extra elements in step 4 do.

Nothing about either element changes as you sweep. Neither one knows<br>which way it is pointing, and neither one is more sensitive in any<br>direction than it was before. The whole response comes from the phase<br>relationship between two separated measurements.

This is the pivot the whole subject turns on. Directionality is something<br>you construct out of separated measurements. It is not something a<br>transducer has.

Step 4 of 7

More elements make one longer aperture.

Add more elements along the same line. More cancellation directions<br>appear, and the one direction where everything still adds gets narrower. For<br>N elements spaced d apart, the beam narrows to roughly λ/L, where<br>L = N·d is the total length of the array.

The count is not what matters. The length is. Two arrays<br>of the same...

element step range wavelength elements distance

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